Cita: "Idolenz"Σ/n (exempting outliers)
No, as far as I remember there is no calculation. The median is used, which automatically avoids all outlyers (both high and low).
Median in this case, when lining up all values, the value that is exactly in the middel (or average of the two values in the middle if the amount of values inserted can be divided by 2).
Explantion by Xavier to be found in the second post:
https://en.numista.com/forum/topic74862.html
